Hanzo Hattori

Some may know the answer Im sure...


Three friends check into a hotel for the night and the clerk tells them the bill is $30, payable in advance.

So, they each pay the clerk $10 and go to their room. A few minutes later, the clerk realizes he has made an error and overcharged the three by $5. He asks the bellboy to return $5 to the three friends who had just checked in.

The bellboy sees this as an opportunity to make $2 as he reasons that the three friends would have a tough time dividing $5 evenly among them; so he decides to tell them that the clerk made a mistake of only $3, giving a dollar back to each of the friends. He pockets the leftover $2 and goes home for the day!

Now, each of the three friends gets a dollar back, thus they each paid $9 for the room which is a total of $27 for the night. We know the bellhop pocketed $2 and adding that to the $27, you get $29, not $30 which was originally spent.

Where did the other dollar go? :biggrin4: :biggrin4: :biggrin4:

sgalextoh

It's very similar to another riddle I've read before....

Anyway it's not a matter of missing dollar....

each pax pay $10 ( initial)
$10 x 3 =$30
Each of them gets back $1
So it's only $9 each.
$9 x 3 = $27
$1 x 3 = $3
Bill is $25 after refund and bellboy pocket $2
$25 + $2 = $27
So the 3 of them still paid $27 which $2 is being pocket by the bellboy.