jovylee

Theorem: All numbers are equal.
Proof: Choose arbitrary a and b, and let t = a + b. Then

a + b = t
(a + b)(a - b) = t(a - b)
a^2 - b^2 = ta - tb
a^2 - ta = b^2 - tb
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
(a - t/2)^2 = (b - t/2)^2
a - t/2 = b - t/2
a = b

So all numbers are the same, and math is pointless.

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Hirakawa

This is the same theory to prove 1 = 2... but there is a big mistake at line 2...

(a + b)(a - b) = t(a - b)

if a = b in the end result, (a - b) will become 0 and we cannot divide by 0 because it is infinity and 0 divided by 0 can be anything...

ireneyksoh

o_0"

sovering

what.. ?

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